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Strength of Materials - Section 1 (5)

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Strength of Materials - Section 1

Here you will find all the important problems and questions of s
Strength of Material. We provide all the necessary questions which are asked in exam.

33. 

A simply supported beam of span L carries a concentrated load W at its mid-span. The maximum bending moment M is

A. 126-6.44-1
B. 126-6.44-2
C. 126-6.44-3
D. 126-6.44-4
E. 126-6.44-5

Answer: Option B

Explanation:

No answer description available for this question. Let us discuss.

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34. 

In case of an eccentric loading on a bracket subjected to moment M, the tangential force developed in any rivet, at right angles to its radius vector r is

A. 125-6.30-1
B. 125-6.30-2
C. 125-6.30-3
D. 125-6.30-4

Answer: Option A

Explanation:

No answer description available for this question. Let us discuss.

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35. 

In the cantilever truss as shown in below figure, the horizontal component of the reaction at A, is

136-6.184-1

 

A. 30 tonnes
B. 60 tonnes
C. 90 tonnes
D. 120 tonnes
E. 150 tonnes.

Answer: Option A

Explanation:

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36. 

If the shear force along a section of a beam is zero, the bending moment at the section is

A. zero
B. maximum
C. minimum
D. average of maximum-minimum
E. none of these.

Answer: Option B

Explanation:

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37. 

A closely coiled helical spring of radius R, contains n turns and is subjected to an axial load W. If the radius of the coil wire is r and modulus of rigidity of the coil material is C, the stress developed in the helical spring is

A. 140-6.212-1
B. 140-6.212-2
C. 140-6.212-3
D. 140-6.212-4

Answer: Option B

Explanation:

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38. 

If two forces acting at a joint are not along the straight line, then for the equilibrium of the joint

A. one of the forces must be zero
B. each force must be zero
C. forces must be equal and of the same sign
D. forces must be equal in magnitude but opposite in sign.

Answer: Option B

Explanation:

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39. 

A beam of length L is pinned at both ends and is subjected to a concentrated bending couple of moment M at its centre. The maximum bending moment in the beam is

A. M
B. M/2
C. M/3
D. ML/2

Answer: Option A

Explanation:

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40. 

A uniform girder simply supported at its ends is subjected to a uniformly distributed load over its entire length and is propped at the centre so as to neutralise the deflection. The net B.M. at the centre will be

A. WL
B. 126-6.44-3
C. 128-6.78-1
D. 128-6.78-2
E. 128-6.78-3

Answer: Option D

Explanation:

No answer description available for this question. Let us discuss.

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