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Time and Work - General Questions

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  • Time and Work - General Questions
1. 

A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?

A. 30 days
B. 40 days
C. 60 days
D. 70 days

Answer: Option C

Explanation:

Let A's 1 day's work = x and B's 1 day's work = y.

Then, x + y = 1 and 16x + 44y = 1.
30
Solving these two equations, we get: x = 1 and y = 1
60 60
 B's 1 day's work = 1 .
60

Hence, B alone shall finish the whole work in 60 days.

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2. 

A and B can do a job together in 7 days. A is 11-div-3by4times as efficient as B. The same job can be done by A alone in :

A. 9 1/3 days
B. 11 days
C. 12 1/4 days
D. 16 1/3 days

Answer: Option B

Explanation:

(A's 1 day's work) : (B's 1 day's work) = 7 : 1   =   7 : 4.
4

Let A's and B's 1 day's work be 7x and 4x respectively.

Then, 7x + 4x = 1     =>     11x = 1     =>     x = 1 .
7 7 77
Therefore A's 1 day's work = 1-sym-oparen-h1 1 x 7 1-sym-cparen-h1 = 1 .
77 11
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3. 

X can do a piece of work in 40 days. He works at it for 8 days and then Y finished it in 16 days. How long will they together take to complete the work?

A. 13 1/3 days
B. 15 days
C. 20 days
D. 26 days

Answer: Option A

Explanation:

Work done by X in 8 days = 1-sym-oparen-h1 1 x 8 1-sym-cparen-h1 = 1 .
40 5
Remaining work = 1-sym-oparen-h1 1 - 1 1-sym-cparen-h1 = 4 .
5 5
Now, 4 work is done by Y in 16 days.
5
Whole work will be done by Y in 1-sym-oparen-h1 16 x 5 1-sym-cparen-h1 = 20 days.
4
Therefore X's 1 day's work = 1 , Y's 1 day's work = 1 .
40 20
(X + Y)'s 1 day's work = 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1 = 3 .
40 20 40
Hence, X and Y will together complete the work in   40 1-sym-cparen-h1 = 13 1 days.
3 3
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4. 

A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:

A. 5 days
B. 6 days
C. 10 days
D. 10 1/2 days

Answer: Option C

Explanation:

(B + C)'s 1 day's work = 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1 = 7 .
9 12 36
Work done by B and C in 3 days = 1-sym-oparen-h1 7 x 3 1-sym-cparen-h1 = 7 .
36 12
Remaining work = 1-sym-oparen-h1 1 - 7 1-sym-cparen-h1 = 5 .
12 12
Now, 1 work is done by A in 1 day.
24
So, 5 work is done by A in 1-sym-oparen-h1 24 x 5 1-sym-cparen-h1 = 10 days.
12 12
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5. 

A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in :

A. 4 days
B. 6 days
C. 8 days
D. 12 days

Answer: Option C

Explanation:

(A + B + C)'s 1 day's work = 1 ;
6
(A + B)'s 1 day's work = 1 ;
8
(B + C)'s 1 day's work = 1 .
12
Therefore (A + C)'s 1 day's work
= 1-sym-oparen-h1 2 x 1 1-sym-cparen-h1 - 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1
6 8 12
 
= 1-sym-oparen-h1 1 - 5 1-sym-cparen-h1
3 24
 
= 3
24
 
= 1 .
8
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6. 

Twenty women can do a work in sixteen days. Sixteen men can complete the same work in fifteen days. What is the ratio between the capacity of a man and a woman?

A. 3 : 4
B. 4 : 3
C. 5 : 3
D. Data inadequate

Answer: Option B

Explanation:

(20 x 16) women can complete the work in 1 day.

 1 woman's 1 day's work = 1 .
320

(16 x 15) men can complete the work in 1 day.

 1 man's 1 day's work = 1
240
So, required ratio
= 1 : 1
240 320
 
= 1 : 1
3 4
  = 4 : 3 (cross multiplied)
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7. 

A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in :

A. 4 days
B. 6 days
C. 8 days
D. 18 days

Answer: Option A

Explanation:

Ratio of rates of working of A and B = 2 : 1.

So, ratio of times taken = 1 : 2.

B's 1 day's work = 1 .
12
Therefore A's 1 day's work = 1 ; (2 times of B's work)
6
(A + B)'s 1 day's work = 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1 = 3 = 1 .
6 12 12 4

So, A and B together can finish the work in 4 days.

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8. 

A and B can do a piece of work in 30 days, while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work?

A. 18 days
B. 24 days
C. 30 days
D. 36 days

Answer: Option A

Explanation:

2(A + B + C)'s 1 day's work = 1-sym-oparen-h1 1 + 1 + 1 1-sym-cparen-h1 = 15 = 1 .
30 24 20 120 8
Therefore, (A + B + C)'s 1 day's work = 1 = 1 .
2 x 8 16
Work done by A, B, C in 10 days = 10 = 5 .
16 8
Remaining work = 1-sym-oparen-h1 1 - 5 1-sym-cparen-h1 = 3 .
8 8
A's 1 day's work = 1-sym-oparen-h1 1 - 1 1-sym-cparen-h1 = 1 .
16 24 48
Now, 1 work is done by A in 1 day.
48
So, 3 work will be done by A in 1-sym-oparen-h1 48 x 3 1-sym-cparen-h1 = 18 days.
8 8
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