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X can do a piece of work in 40 days. He works at it for 8 days and then Y finished it in 16 days. How long will they together take to complete the work?

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1. 

X can do a piece of work in 40 days. He works at it for 8 days and then Y finished it in 16 days. How long will they together take to complete the work?

[A]. 13 1/3 days
[B]. 15 days
[C]. 20 days
[D]. 26 days

Answer: Option A

Explanation:

Work done by X in 8 days = 1-sym-oparen-h1 1 x 8 1-sym-cparen-h1 = 1 .
40 5
Remaining work = 1-sym-oparen-h1 1 - 1 1-sym-cparen-h1 = 4 .
5 5
Now, 4 work is done by Y in 16 days.
5
Whole work will be done by Y in 1-sym-oparen-h1 16 x 5 1-sym-cparen-h1 = 20 days.
4
Therefore X's 1 day's work = 1 , Y's 1 day's work = 1 .
40 20
(X + Y)'s 1 day's work = 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1 = 3 .
40 20 40
Hence, X and Y will together complete the work in   40 1-sym-cparen-h1 = 13 1 days.
3 3
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