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Time and Work - General Questions (4)

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  • Time and Work - General Questions
25. 

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

A. 4 days
B. 5 days
C. 6 days
D. 7 days

Answer: Option A

Explanation:

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

Then, 6x + 8y = 1 and 26x + 48y = 1 .
10 2
Solving these two equations, we get : x = 1 and y = 1 .
100 200
(15 men + 20 boy)'s 1 day's work = 1-sym-oparen-h1 15 + 20 1-sym-cparen-h1 = 1 .
100 200 4

 15 men and 20 boys can do the work in 4 days.

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26. 

A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?

A. Rs. 375
B. Rs. 400
C. Rs. 600
D. Rs. 800

Answer: Option B

Explanation:

C's 1 day's work = 1 - 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1 = 1 - 7 = 1 .
3 6 8 3 24 24
A's wages : B's wages : C's wages = 1 : 1 : 1 = 4 : 3 : 1.
6 8 24
C's share (for 3 days) = Rs. 1-sym-oparen-h1 3 x 1 x 3200 1-sym-cparen-h1 = Rs. 400.
24
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27. 

A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:

A. 20 days
B. 22 1/2 days
C. 25 days
D. 30 days

Answer: Option B

Explanation:

Ratio of times taken by A and B = 1 : 3.

The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.

If difference of time is 2 days, B takes 3 days.

If difference of time is 60 days, B takes 1-sym-oparen-h1 3 x 60 1-sym-cparen-h1 = 90 days.
2

So, A takes 30 days to do the work.

A's 1 day's work = 1
30
B's 1 day's work = 1
90
(A + B)'s 1 day's work = 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1 = 4 = 2
30 90 90 45
 A and B together can do the work in 45 = 22 1 days.
2 2
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28. 

A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?

A. 12 days
B. 15 days
C. 16 days
D. 18 days

Answer: Option B

Explanation:

A's 2 day's work = 1-sym-oparen-h1 1 x 2 1-sym-cparen-h1 = 1 .
20 10
(A + B + C)'s 1 day's work = 1-sym-oparen-h1 1 + 1 + 1 1-sym-cparen-h1 = 6 = 1 .
20 30 60 60 10
Work done in 3 days = 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1 = 1 .
10 10 5
Now, 1 work is done in 3 days.
5

 Whole work will be done in (3 x 5) = 15 days.

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29. 

A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:

A. 9 1/5 days
B. 9 2/5 days
C. 9 3/5 days
D. 10

Answer: Option C

Explanation:

(A + B + C)'s 1 day's work = 1 ,
4
A's 1 day's work = 1 ,
16
B's 1 day's work = 1 .
12
Therefore C's 1 day's work = 1 - 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1 = 1-sym-oparen-h1 1 - 7 1-sym-cparen-h1 = 5 .
4 16 12 4 48 48
So, C alone can do the work in 48 = 9 3 days.
5 5
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30. 

A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

A. 1/4
B. 1/10
C. 7/15
D. 8/15

Answer: Option D

Explanation:

A's 1 day's work = 1 ;
15
B's 1 day's work = 1 ;
20
(A + B)'s 1 day's work = 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1 = 7 .
15 20 60
(A + B)'s 4 day's work = 1-sym-oparen-h1 7 x 4 1-sym-cparen-h1 = 7 .
60 15
Therefore, Remaining work = 1-sym-oparen-h1 1 - 7 1-sym-cparen-h1 = 8 .
15 15
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