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Time and Work - General Questions (2)

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  • Time and Work - General Questions
9. 

A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in :

A. 8 days
B. 10 days
C. 12 days
D. 15 days

Answer: Option C

Explanation:

(A + B)'s 1 day's work = 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1 = 1 .
15 10 6
Work done by A and B in 2 days = 1-sym-oparen-h1 1 x 2 1-sym-cparen-h1 = 1 .
6 3
Remaining work = 1-sym-oparen-h1 1 - 1 1-sym-cparen-h1 = 2 .
3 3
Now, 1 work is done by A in 1 day.
15
Therefore 2 work will be done by a in 1-sym-oparen-h1 15 x 2 1-sym-cparen-h1 = 10 days.
3 3

Hence, the total time taken = (10 + 2) = 12 days.

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10. 

A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:

A. 4 days
B. 6 days
C. 8 days
D. 12 days

Answer: Option B

Explanation:

Suppose A, B and C take x, x and x days respectively to finish the work.
2 3
Then, 1-sym-oparen-h1 1 + 2 + 3 1-sym-cparen-h1 = 1
x x x 2
6 = 1
x 2

 x = 12.

So, B takes (12/2) = 6 days to finish the work.

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11. 

Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:

A. 15
B. 16
C. 18
D. 25

Answer: Option B

Explanation:

Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.

Suppose Tanya takes x days to do the work.

5 : 4 :: 20 : x     x = 1-sym-oparen-h1 4 x 20 1-sym-cparen-h1
5

 x = 16 days.

Hence, Tanya takes 16 days to complete the work.

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12. 

A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in:

A. 1/24 day
B. 7/24 day
C. 3 3/7 days
D. 4 days

Answer: Option C

Explanation:

Formula: If A can do a piece of work in n days, then A's 1 day's work = 1 .
n
(A + B + C)'s 1 day's work = 1-sym-oparen-h1 1 + 1 + 1 1-sym-cparen-h1 = 7 .
24 6 12 24
Formula: If A's 1 day's work = 1 , then A can finish the work in n days.
n
So, all the three together will complete the job in 1-sym-oparen-h1 24 1-sym-cparen-h1 days = 3 3 days.
7 7
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13. 

Ravi and Kumar are working on an assignment. Ravi takes 6 hours to type 32 pages on a computer, while Kumar takes 5 hours to type 40 pages. How much time will they take, working together on two different computers to type an assignment of 110 pages?

A. 7 hours 30 minutes
B. 8 hours
C. 8 hours 15 minutes
D. 8 hours 25 minutes

Answer: Option C

Explanation:

Number of pages typed by Ravi in 1 hour = 32 = 16 .
6 3
Number of pages typed by Kumar in 1 hour = 40 = 8.
5
Number of pages typed by both in 1 hour = 1-sym-oparen-h1 16 + 8 1-sym-cparen-h1 = 40 .
3 3
Therefore Time taken by both to type 110 pages = 1-sym-oparen-h1 110 x 3 1-sym-cparen-h1 hours
40
= 8 1 hours (or) 8 hours 15 minutes.
4
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14. 

A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?

A. 11 days
B. 13 days
C. 20 3/17 days
D. None of these

Answer: Option B

Explanation:

Ratio of times taken by A and B = 100 : 130 = 10 : 13.

Suppose B takes x days to do the work.

Then, 10 : 13 :: 23 : x     =>     x = 1-sym-oparen-h1 23 x 13 1-sym-cparen-h1     =>     x = 299 .
10 10
A's 1 day's work = 1 ;
23
B's 1 day's work = 10 .
299
(A + B)'s 1 day's work = 1-sym-oparen-h1 1 + 10 1-sym-cparen-h1 = 23 = 1 .
23 299 299 13

Therefore, A and B together can complete the work in 13 days.

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15. 

X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?

A. 6 days
B. 10 days
C. 15 days
D. 20 days

Answer: Option B

Explanation:

Work done by X in 4 days = 1-sym-oparen-h1 1 x 4 1-sym-cparen-h1 = 1 .
20 5
Remaining work = 1-sym-oparen-h1 1 - 1 1-sym-cparen-h1 = 4 .
5 5
(X + Y)'s 1 day's work = 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1 = 8 = 2 .
20 12 60 15
Now, 2 work is done by X and Y in 1 day.
15
So, 4 work will be done by X and Y in 1-sym-oparen-h1 15 x 4 1-sym-cparen-h1 = 6 days.
5 2 5

Hence, total time taken = (6 + 4) days = 10 days.

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16. 

10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?

A. 3
B. 5
C. 7
D. Cannot be determined
E. None of these

Answer: Option C

Explanation:

1 woman's 1 day's work = 1
70
1 child's 1 day's work = 1
140
(5 women + 10 children)'s day's work = 1-sym-oparen-h1 5 + 10 1-sym-cparen-h1 = 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1 = 1
70 140 14 14 7

 5 women and 10 children will complete the work in 7 days.

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