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Problems on Trains - General Questions (3)

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  • Problems on Trains - General Questions
17. 

A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

A. 5 sec
B. 6 sec
C. 7 sec
D. 10 sec

Answer: Option B

Explanation:

Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.

   = 1-sym-oparen-h1 66 x 5 1-sym-cparen-h1m/sec
18
   = 1-sym-oparen-h1 55 1-sym-cparen-h1m/sec.
3
 Time taken to pass the man = 1-sym-oparen-h1 110 x 3 1-sym-cparen-h1sec = 6 sec.
55
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18. 

Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:

A. 9
B. 9.6
C. 10
D. 10.8

Answer: Option D

Explanation:

Relative speed = (60 + 40) km/hr = 1-sym-oparen-h1 100 x 5 1-sym-cparen-h1m/sec = 1-sym-oparen-h1 250 1-sym-cparen-h1m/sec.
18 9

Distance covered in crossing each other = (140 + 160) m = 300 m.

Required time = 1-sym-oparen-h1 300 x 9 1-sym-cparen-h1sec = 54 sec = 10.8 sec.
250 5
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19. 

Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:

A. 30 km/hr
B. 45 km/hr
C. 60 km/hr
D. 75 km/hr

Answer: Option C

Explanation:

Let the speed of the slower train be x m/sec.

Then, speed of the faster train = 2x m/sec.

Relative speed = (x + 2x) m/sec = 3x m/sec.

(100 + 100) = 3x
8

 24x = 200

 x = 25 .
3
So, speed of the faster train = 50 m/sec
3
   = 1-sym-oparen-h1 50 x 18 1-sym-cparen-h1km/hr
3 5

   = 60 km/hr.

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20. 

A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?

A. 230 m
B. 240 m
C. 260 m
D. 270 m

Answer: Option D

Explanation:

Speed = 1-sym-oparen-h1 72 x 5 1-sym-cparen-h1m/sec = 20 m/sec.
18

Time = 26 sec.

Let the length of the train be x metres.

Then, x + 250 = 20
26

 x + 250 = 520

 x = 270.

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21. 

A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?

A. 230 m
B. 240 m
C. 260 m
D. 320 m
E. None of these

Answer: Option A

Explanation:

Relative speed = (120 + 80) km/hr

   = 1-sym-oparen-h1 200 x 5 1-sym-cparen-h1m/sec
18
   = 1-sym-oparen-h1 500 1-sym-cparen-h1m/sec.
9

Let the length of the other train be x metres.

Then, x + 270 = 500
9 9

 x + 270 = 500

 x = 230.

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22. 

A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

A. 3.6 sec
B. 18 sec
C. 36 sec
D. 72 sec

Answer: Option C

Explanation:

Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.

   = 1-sym-oparen-h1 36 x 5 1-sym-cparen-h1m/sec
18

   = 10 m/sec.

Distance to be covered = (240 + 120) m = 360 m.

 Time taken = 1-sym-oparen-h1 360 1-sym-cparen-h1sec = 36 sec.
10
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23. 

Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

A. 36
B. 45
C. 48
D. 49

Answer: Option C

Explanation:

Relative speed = (60+ 90) km/hr

   = 1-sym-oparen-h1 150 x 5 1-sym-cparen-h1m/sec
18
   = 1-sym-oparen-h1 125 1-sym-cparen-h1m/sec.
3

Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.

Required time = 1-sym-oparen-h1 2000 x 3 1-sym-cparen-h1sec = 48 sec.
125
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24. 

A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?

A. 40 sec
B. 42 sec
C. 45 sec
D. 48 sec

Answer: Option A

Explanation:

Formula for converting from km/hr to m/s:   X km/hr = 1-sym-oparen-h1 X x 5 1-sym-cparen-h1 m/s.
18
Therefore, Speed = 1-sym-oparen-h1 45 x 5 1-sym-cparen-h1m/sec = 25 m/sec.
18 2

Total distance to be covered = (360 + 140) m = 500 m.

Formula for finding Time = 1-sym-oparen-h1 Distance 1-sym-cparen-h1
Speed
 Required time = 1-sym-oparen-h1 500 x 2 1-sym-cparen-h1sec = 40 sec.
25
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