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A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

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1. 

A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

[A]. 3.6 sec
[B]. 18 sec
[C]. 36 sec
[D]. 72 sec

Answer: Option C

Explanation:

Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.

   = 1-sym-oparen-h1 36 x 5 1-sym-cparen-h1m/sec
18

   = 10 m/sec.

Distance to be covered = (240 + 120) m = 360 m.

 Time taken = 1-sym-oparen-h1 360 1-sym-cparen-h1sec = 36 sec.
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