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Problems on Trains - General Questions (4)

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  • Problems on Trains
  • Problems on Trains - General Questions
25. 

Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:

A. 50 m
B. 72 m
C. 80 m
D. 82 m

Answer: Option A

Explanation:

Let the length of each train be x metres.

Then, distance covered = 2x metres.

Relative speed = (46 - 36) km/hr

   = 1-sym-oparen-h1 10 x 5 1-sym-cparen-h1m/sec
18
   = 1-sym-oparen-h1 25 1-sym-cparen-h1m/sec
9
2x = 25
36 9

 2x = 100

 x = 50.

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26. 

A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?

A. 65 sec
B. 89 sec
C. 100 sec
D. 150 sec

Answer: Option B

Explanation:

Speed = 1-sym-oparen-h1 240 1-sym-cparen-h1m/sec = 10 m/sec.
24
 Required time = 1-sym-oparen-h1 240 + 650 1-sym-cparen-h1sec = 89 sec
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27. 

A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

A. 120 m
B. 240 m
C. 300 m
D. None of these

Answer: Option B

Explanation:

Speed = 1-sym-oparen-h1 54 x 5 1-sym-cparen-h1m/sec = 15 m/sec.
18

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

Then, x + 300 = 15
36

 x + 300 = 540

 x = 240 m.

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28. 

Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:

A. 1 : 3
B. 3 : 2
C. 3 : 4
D. None of these

Answer: Option B

Explanation:

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

27x + 17y = 23
x+ y

 27x + 17y = 23x + 23y

 4x = 6y

x = 3 .
y 2
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29. 

The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:

A. 200 m
B. 225 m
C. 245 m
D. 250 m

Answer: Option C

Explanation:

Speed = 1-sym-oparen-h1 45 x 5 1-sym-cparen-h1m/sec = 1-sym-oparen-h1 25 1-sym-cparen-h1m/sec.
18 2

Time = 30 sec.

Let the length of bridge be x metres.

Then, 130 + x = 25
30 2

 2(130 + x) = 750

 x = 245 m.

 

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30. 

A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:

A. 45 km/hr
B. 50 km/hr
C. 54 km/hr
D. 55 km/hr

Answer: Option B

Explanation:

Speed of the train relative to man = 1-sym-oparen-h1 125 1-sym-cparen-h1m/sec
10
   = 1-sym-oparen-h1 25 1-sym-cparen-h1m/sec.
2
   = 1-sym-oparen-h1 25 x 18 1-sym-cparen-h1km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

 x - 5 = 45          x = 50 km/hr.

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31. 

A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

A. 120 metres
B. 180 metres
C. 324 metres
D. 150 metres

Answer: Option D

Explanation:

Speed = 1-sym-oparen-h1 60 x 5 1-sym-cparen-h1m/sec = 1-sym-oparen-h1 50 1-sym-cparen-h1m/sec.
18 3

Length of the train = (Speed x Time).

 Length of the train = 1-sym-oparen-h1 50 x 9 1-sym-cparen-h1m = 150 m.
3
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