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Electronic Devices and Circuits - Section 1 (5)

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  • Electronic Devices and Circuits - Section 1
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Electronic Devices and Circuits - Section 1

33. 

A transistor has two p-n junctions. The batteries should be connected such that

A. both junctions are forward biased
B. both junctions are reverse biased
C. one junction is forward biased and the other is reverse biased
D. none of the above

Answer: Option C

Explanation:

Emitter-base junction is forward biased and base collector junction is reverse biased.

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34. 

The number of doped regions in PIN diode is

A. 1
B. 2
C. 3
D. 1 or 2

Answer: Option B

Explanation:

A PIN diode has p and n doped regions separated by intrinsic layer.

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35. 

An LED has a rating of 2 V and 10 mA. It is used along with 6V battery. The range of series resistance is

A. 0 to 200 Ω
B. 200 - 400 Ω
C. 200 Ω and above
D. 400 Ω and above

Answer: Option D

Explanation:

R = 75-268-1 = 400Ω.

R must be at least 400Ω so that current in LED does not exceed 10 mA.

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36. 

In an n-p-n transistor, the majority carriers in the base are

A. electrons
B. holes
C. both holes and electrons
D. either holes or electrons

Answer: Option A

Explanation:

Emitter is n type and emits electrons which diffuse through the base.

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37. 

In a p type material the Fermi level is 0.3 eV above valence band. The concentration of acceptor atoms is increased. The new position of Fermi level is likely to be

A. 0.5 eV above valence band
B. 0.28 eV above valence band
C. 0.1 eV above valence band
D. below the valence band

Answer: Option B

Explanation:

Addition of acceptor atom brings Fermi level closer to valence band.

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38. 

Ferrite have

A. low copper loss
B. low eddy current loss
C. low resistivity
D. higher specific gravity compared to iron

Answer: Option C

Explanation:

Ferrite is a low density material of composition with Fe2O3 x O, where x is a bivalent metal, such as Cobart, Ni, Mn. These magnetic materials having very low loss of current and used in high frequency circuit.

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39. 

When a voltage is applied to a semiconductor crystal then the free electrons will flow.

A. towards positive terminal
B. towards negative terminal
C. either towards positive terminal or negative terminal
D. towards positive terminal for 1 μs and towards negative terminal for next 1 μs

Answer: Option A

Explanation:

Since electrons are negatively charged they will flow towards positive terminal.

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40. 

At very high temperatures the extrinsic semi conductors become intrinsic because

A. drive in diffusion of dopants and carriers
B. band to band transition dominants over impurity ionization
C. impurity ionization dominants over band to band transition
D. band to band transition is balanced by impurity ionization

Answer: Option B

Explanation:

Covalent bonds are broken.

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