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Automatic Control Systems - Section 1 (6)

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Automatic Control Systems - Section 1

41. 

For a first order system having transfer function 12-22 the unit impulse response is

A. e-t/T
B. T e-t/T
C. 12-24-3
D. T2 e-t/T

Answer: Option C

Explanation:

41-24

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42. 

Assertion (A): Potentiometers can not be used as error detectors in position control systems.

Reason (R): The resolution of a potentiometer places an upper limit on its accuracy

A. Both A and R are correct and R is correct explanation of A
B. Both A and R are correct but R is not correct explanation of A
C. A is correct but R is wrong
D. R is correct but A is wrong

Answer: Option D

Explanation:

Potentiometers are used as error detectors.

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43. 

For the system of the given figure, the damping ratio of closed loop poles is

17-92

A. 1.5
B. 1
C. 0.5
D. 0.25

Answer: Option C

Explanation:

The standard form of characteristic equation is 42-93

Therefore 42-93-1

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44. 

If a system is to follow arbitrary inputs accurately the bandwidth should be

A. large
B. small
C. very small
D. neither small nor large

Answer: Option A

Explanation:

Arbitrary inputs require large bandwidth.

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45. 

In the given figure shows pole-zero plot. If steady state gain is 2 the transfer function G(s) is

22-187

A. 22-187-1
B. 22-187-2
C. 22-187-3
D. 22-187-4

Answer: Option A

Explanation:

The zero at - 1 gives the term (s + 1) in the numerator.

The poles at (- 2 + j1) and (- 2 - j1) give (s2 + 4s + 5) term is the denominator. Gain is 2.

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46. 

For the system of the given figure the transfer function 11-12

11-12-(1)

A. 11-12-1
B. 11-12-2
C. 11-12-3
D. 11-12-4

Answer: Option B

Explanation:

40-12 E0(s) = [I(s)][Z2(s)] or 40-12-1

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47. 

Whether a linear system is stable or unstable that it

A. is a property of the system only
B. depends on the input function only
C. both (a) and (b)
D. either (a) or (b)

Answer: Option A

Explanation:

Stability is a property of the system only.

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48. 

For the system in the given figure. The transfer function C(s)/R(s) is

12-20

A. G1 + G2 + 1
B. G1 G2 + 1
C. G1 G2 + G2 + 1
D. G1 G2 + G1 + 1

Answer: Option C

Explanation:

Transfer function = (G1 + 1) G2 + 1 = G1 G2 + G2 + 1.

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