The analog signal m(t) is given below m(t) = 4 cos 100 pt + 8 sin 200 pt + cos 300 pt, the Nyquist sampling rate will be

m (t) = 4 cos 100 pt + 8 sin 200 pt + cos 300 pt

Nyquist sampling freq f_s ≤ 2f_m where f_m is highest frequency component in given signal and highest f_m in 3^rd part

2pf_mt = 300 pt

f_m = 150 Hz

f_s = 2 x 150 p 300 Hz