Consider the probability density f(x) = ae-b|x| where x is a random variable whose allowable values range from x = - ∞ to x = + ∞. P(1 ≤ x ≤ 2)

Consider the probability density f(x) = ae^-b|x| where x is a random variable whose allowable values range from x = - ∞ to x = + ∞. P(1 ≤ x ≤ 2)

Answer: Option C

Explanation:

P(x) = 11-04-29 ae^-b|x|d_x

to get 11-04-29-1 apply 11-04-29-2 ae^bxdx + 11-04-29-3 ae^-bxd_x,

we get 11-04-29-4 =