7BF 16 = __________ 2
| 1. |
|
|||||||
Answer: Option B Explanation: 7BF16 = 7 x 162 + 11 x 161 + 15 x 160 = 1983 in decimal = 0111 1011 1111 in binary. |
Leave a Comment
Electronics & Communication Engineering :: Electronics and Communication Engineering : More Exercises
- Materials and Components - Section 1
- Networks Analysis and Synthesis - Section 1
- Measurements and Instrumentation - Section 1
- Analog Electronics - Section 1
- Automatic Control Systems - Section 1
- Radio Receivers - Section 1
- Satellite Communication - Section 1
- Signals and Systems - Section 1
- Exam Questions Papers - Exam Paper 1
- Electronic Devices and Circuits - Section 1
- Electromagnetic Field Theory - Section 1
- Power Electronics - Section 1
- Digital Electronics - Section 1
- Communication Systems - Section 1
- Microwave Communication - Section 1
- Microprocessors - Section 1
- Matching Questions - Section 1