Minimum number of 2-input NAND gates required to implement the function F = (x + y) (Z + W) is

1.

Minimum number of 2-input NAND gates required to implement the function F = (x + y) (Z + W) is

[A].	3
[B].	4
[C].	5
[D].	6

Answer: Option B

Explanation:

F = (x + y) (z + w) = xy.(z + w)

= xyz + xyw

70-522 minimum no. of 2 input NAND gate.

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