In the given figure the input is x(t) = A sin ωt. The steady state output y(t) =

1.

In the given figure the input is x(t) = A sin ωt. The steady state output y(t) =

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[A].	A sin (ωt + φ) where φ = tan-1 \|G(jω)\|
[B].	\|G(jω)\| A sin [ωt + ∠G(jω)]
[C].	\|G(jω)\| A sin [2ωt + ∠G(jω)]
[D].	A G(jω) sin [ωt + ∠G(jω)]

Answer: Option B

Explanation:

The magnitudes A and G(jω) are multiplied and phase angles are added.

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