In figure ID = 4 mA. Then VS =

1.

In figure I_D = 4 mA. Then V_S =

310-147-1

[A].	20 V
[B].	4.4 V
[C].	0.4 V
[D].	0.44 V

Answer: Option B

Explanation:

V_S = I_SR_S = 4 x 10^-3 x 1.1 x 10³ = 4.4 V.

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