In figure, VEB = 0.6 V, Î² = 99. Then VC and IC are

1.

In figure, VEB = 0.6 V, β = 99. Then VC and IC are

316-221-1

[A].	9.3 V and 1.98 mA respectively
[B].	4.6 V and 1.98 mA respectively
[C].	9.3 V and 0.02 mA respectively
[D].	4.6 V and 0.02 mA respectively

Answer: Option A

Explanation:

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V_C = 20 - 1.98 x 10^-3 x 5.4 x 10³ 1-sym-aa= 9.3 V.

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