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KOP: Impulse and Momentum - General Questions (3)

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KOP: Impulse and Momentum - General Questions

17. 

15-04

In cases of emergency, the gas actuator can be used to move a 75-kg block B by exploding a charge C near a pressurized cylinder of negligible mass. As a result of the explosion, the cylinder fractures and the released gas forces the front part ofthe cylinder, A, to move B and the floor is mu (11) = 0.5, determine the impulse that the actuator must impart to B.

A. Imp = 147.2 N-s
B. Imp = 132.2 N-s
C. Imp = 15.00 N-s
D. Imp = 162.2 N-s

Answer: Option D

Explanation:

No answer description available for this question. Let us discuss.

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18. 

15-19

A basket and its contents weigh 10 lb. A 20-lb monkey grabs the other end of the rope and very quickly (almost instantaneously) accelerates by pulling hard on the rope until he is moving with a constant speed of vm/r = 2 ft/s measured relative to the rope. The monkey then continues climbing at this constant rate relative to the rope for 3 seconds. How fast is the basket rising at the end of the 3 seconds? Neglect the mass of the pulley and the rope.

A. vbasket = 33.5 ft/s
B. vbasket = 32.2 ft/s
C. vbasket = 96.6 ft/s
D. vbasket = 97.9 ft/s

Answer: Option A

Explanation:

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19. 

15-13

The drop hammer H has a weight of 900 lb and falls from rest. H has a weight of 900 lb and falls from rest h = 3 ft onto a forged anvil plate P that has a weight of 500 lb. The plate is mounted on a set of springs which have a combined stiffness of kT = 500 lb/ft. Determine (a) the velocity of P and H just after collision and (b) the maximum compression in the springs caused by the impact. The coefficient of restitution between the hammer and the plate is e = 0.6. Neglect friction along the vertical guide posts A and B.

A. vH2 = 3.97 ft/s, vP2 = 17.87 ft/s, x = 4.15 ft
B. vH2 = 8.94 ft/s, vP2 = 8.94 ft/s, x = 2.57 ft
C. vH2 = 5.96 ft/s, vP2 = 14.30 ft/s, x = 3.52 ft
D. vH2 = 20.8 ft/s, vP2 = 12.51 ft/s, x = 3.20 ft

Answer: Option C

Explanation:

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20. 

15-02

A golf ball having a mass of 40 g is struck such that it has an initial velocity of 200 m/s as shown. Determine the horizontal and vertical components of the impulse given to the ball.

A. Impx = 4.00 N-s, Impy = 6.93 N-s
B. Impx = 6.93 N-s, Impy = 4.00 N-s
C. Impx = 6.93 N-s, Impy = 4.39 N-s
D. Impx = 4.00 N-s, Impy = 7.32 N-s

Answer: Option B

Explanation:

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