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Networks Analysis and Synthesis - Section 1 (2)

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Networks Analysis and Synthesis - Section 1

9. 

In the circuit shown in given figure, the values of i(0+) and I(∞), will be respectively

146-1024-1

 

A. zero and 1.5 A
B. 1.5 A and 3 A
C. 3 A and zero
D. 3 A and 1.5 A

Answer: Option C

Explanation:

174-1024-1

I(t) = 6 e-t - 3 e-0.5t

at t = 0, I(0) = 3A

at t = ∞, I(∞) = 0.

 

 
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10. 

The time constant of the circuit in figure shown.

131-819-1

A. RC
B. 131-819-2
C. 131-819-3
D. 131-819-4

Answer: Option B

Explanation:

Time constant1-sym-imp Req.C

when V is shorted and R is seen from C then Req = R || R = R/2

169-819-1

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11. 

In an ac circuit, the maximum and minimum values of power factor can be

A. 2 and 0
B. 1 and 0
C. 0 and -1
D. 1 and -1

Answer: Option B

Explanation:

Power factor is maximum and equal to 1 for purely resistive load. Power factor is minimum and equal to zero for purely reactive load.

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12. 

The current rating of a cable depends on

A. length of cable
B. diameter of cable
C. both length and diameter of cable
D. none of the above

Answer: Option B

Explanation:

Current rating depends only on area of cross-section and hence diameter.

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13. 

The circuit in figure will act as ideal current source with respect to terminals A and B when frequency is

115-597-1

A. 0
B. 1 rad/sec
C. 4 rad/sec
D. 16 rad/sec

Answer: Option B

Explanation:

When ω = 4 rad/sec ωL and 165-597-1 are equal.

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14. 

The electrical energy required to heat a bucket of water to a certain temperature is 2 kWh. If heat losses, are 25%, the energy input is

A. 2.67 kWh
B. 3 kWh
C. 2.5 kWh
D. 3.5 kWh

Answer: Option A

Explanation:

Since 25% of input is lost, 0.75 Input = 2 or input = 158-19-1

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15. 

A series RL circuit has 101-330-1 If a voltage 4 sint + 4t is applied, the steady state current will be

A. 4 sin (4t - 45°)
B. 101-330-2
C. 101-330-3
D. 101-330-4

Answer: Option B

Explanation:

R = 4 Ω, L = 1 H, ω = 4 rad/sec, XL = 4 Ω

162-330-1

162-330-1

162-330-3

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16. 

A current is flowing through a conductor with non-uniform area of cross-section. Then

A. current will be different at different cross-sections.
B. current will be the same at all the cross-sections.
C. current will be different but current density will be same at all the cross-sections
D. current will be the same but current density will be different at different cross-sections.

Answer: Option D

Explanation:

Current density = current/area of cross-section. Same current throughout the conductor.

Since, area of cross-section is non-uniform, current density will be different at different cross-sections.

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