Const (2)

What will be the output of the program?

#include<stdio.h>
#include<stdlib.h>

union employee
{
char name[15];
int age;
float salary;
};
const union employee e1;

int main()
{
strcpy(e1.name, "K");
printf("%s %d %f", e1.name, e1.age, e1.salary);
return 0;
}

A.	Error: RValue required
B.	Error: cannot convert from 'const int ' to 'int const'
C.	Error: LValue required in strcpy
D.	No error

Answer: Option D

Explanation:

The output will be (in 16-bit platform DOS):

K 75 0.000000

10.

What will be the output of the program?

#include<stdio.h>

int main()
{
    int y=128;
    const int x=y;
    printf("%d\n", x);
    return 0;
}

Answer: Option A

Explanation:

Step 1: int y=128; The variable 'y' is declared as an integer type and initialized to value "128".

Step 2: const int x=y; The constant variable 'x' is declared as an integer and it is initialized with the variable 'y' value.

Step 3: printf("%d\n", x); It prints the value of variable 'x'.

Hence the output of the program is "128"