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Force System Resultants - General Questions (2)

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Force System Resultants - General Questions

9. 

pg4-20

This structural connection is subjected to the 8,000-lb force. Replace this force by an equivalent force and couple acting at the center of the bolt group, O.

A. F = (6400i+4800j) lb, M = (-3.20i+7.20j) kip-ft
B. F = (-6400i-4800j) lb, M = -400k kip-ft
C. F = (-6400i-4800j) lb, M = (-3.20i-7.20j) kip-ft
D. F = (6400i+4800j) lb, M = 400k kip-ft

Answer: Option B

Explanation:

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10. 

pg4-7

Determine the moment of the force at A about point P. Use a vector analysis and express the result in Cartesian vector form.

A. MP = (600i-200k) N-m
B. MP = (800i-200j+1200k) N-m
C. MP = (1200i+100k) N-m
D. MP = (400i-200j+1200k) N-m

Answer: Option D

Explanation:

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11. 

pg4-29

The three forces acting on the water tank represent the effect of the wind. Replace this system by a single resultant force and specify its vertical location from point O.

A. R = 600 lb, d = 65.0 ft below O
B. R = 600 lb, d = 130.4 ft below O
C. R = 600 lb, d = 65.0 ft above O
D. R = 600 lb, d = 130.4 ft above O

Answer: Option D

Explanation:

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12. 

pg4-8

The man at B exerts a force of 140N on the rope attached to the end of beam AC as shown. Determine the moment of this force about the base of the beam at A.

A. MA = (720i-360k) N-m
B. MA = (-720i+360k) N-m
C. MA = (-720i-360k) N-m
D. MA = (720i+360k) N-m

Answer: Option C

Explanation:

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13. 

pg4-5

Determine the moment of the force at A about point P. Use a vector analysis and express the result in Cartesian vector form.

A. MP = (160i+240j+40k) N-m
B. MP = (380i+160j+400k) N-m
C. MP = (280i+200j+400k) N-m
D. MP = (40i+80k) N-m

Answer: Option D

Explanation:

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14. 

pg4-2a

Determine the magnitude and direction of the moment of the force at A about point P.

A. Mp = 143.5 ft-lb ccw (1)
B. Mp = 1191 ft-lb ccw (1)
C. Mp = 1104 ft-lb ccw (1)
D. Mp = 1200 ft-lb ccw (1)

Answer: Option C

Explanation:

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15. 

pg4-26

The resultant force of a wind loading acts perpendicular to the face of the sign as shown. Replace this force by an equivalent force and couple moment acting at point O.

A. F = -120i lb, M = (-3000j+1800k) lb-ft
B. F = -120i lb, M = 3500i lb-ft
C. F = -120i lb, M = -3500j lb-ft
D. F = -120i lb, M = 3500k lb-ft

Answer: Option A

Explanation:

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16. 

pg4-27

Replace the force F, having a magnitude of F = 40 lb and acting at B, by an equivalent force and couple moment at A.

A. F = (32i-24k) lb, M = (-120i+96j-160k) lb-ft
B. F = (32i-24k) lb, M = 233k lb-ft
C. F = (32i-24k) lb, M = -72k lb-ft
D. F = (32i-24k) lb, M = (-120i+160j+40k) lb-ft

Answer: Option A

Explanation:

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