Series Circuits - General Questions (2)

Directions to Solve

Series Circuits - General Questions

9.

A series circuit has a 24 V source and a total resistance of 120 . The current through each resistor is

A.	24 mA
B.	200 mA
C.	120 mA
D.	20 mA

Answer: Option B

Explanation:

No answer description available for this question.

10.

The total resistance of eight 5.6 k resistors in series is

A.	8 Ω
B.	5,600 Ω
C.	4,480 Ω
D.	44,800Ω

Answer: Option D

Explanation:

No answer description available for this question.

11.

Five resistors are connected in a series and there is a current of 3 A into the first resistor. The amount of current into the second resistor is

A.	3 A
B.	1 A
C.	4 A
D.	0.3 A

Answer: Option

Explanation:

No answer description available for this question.

12.

If a 6 V and a 9 V source are connected series aiding, the total voltage is

A.	6 V
B.	9 V
C.	3 V
D.	15 V

Answer: Option D

Explanation:

No answer description available for this question.

13.

There are five resistors in a given series circuit and each resistor has 6 V dropped across it. The source voltage

A.	is 6 V
B.	depends on the current flow
C.	depends on the resistor values
D.	is 30 V

Answer: Option D

Explanation:

No answer description available for this question.

14.

Three 680 resistors are connected in series with a 470 V source. Current in the circuit is

A.	69 mA
B.	230 mA
C.	23 mA
D.	690 mA

Answer: Option B

Explanation:

No answer description available for this question.

15.

Two resistors are in series: a 5.6 k resistor and a 4.7 k resistor. The voltage drop across the 5.6 k resistor is 10 V. The voltage across the 4.7 k resistor is

A.	8.39 V
B.	10 V
C.	2.32 V
D.	0 V

Answer: Option A

Explanation:

No answer description available for this question.

16.

All the voltage drops and the source voltage added together in a series circuit is equal to

A.	the total of the voltage drops
B.	the source voltage
C.	zero
D.	the total of the source voltage and the voltage drops

Answer: Option C

Explanation:

No answer description available for this question.

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