Ohm's Law - General Questions (2)

Directions to Solve

Ohm's Law - General Questions

9.

How much current is produced by a voltage of 18 kV across a 15 k resistance?

A.	1.2 A
B.	12 A
C.	120 mA
D.	12 mA

Answer: Option A

Explanation:

No answer description available for this question.

10.

How much resistance is needed to draw 17.6 mA from a 12 volt source?

A.	212 Ω
B.	6.8 kΩ
C.	68 Ω
D.	680 Ω

Answer: Option D

Explanation:

No answer description available for this question.

11.

If 24 V are applied across a resistor and there are 10.9 mA of current, the resistance is

A.	220 kΩ
B.	22 kΩ
C.	2.2 kΩ
D.	220 kΩ

Answer: Option C

Explanation:

No answer description available for this question.

12.

If you wish to increase the amount of current in a resistor from 120 mA to 160 mA by changing the 24 V source, what should the new voltage setting be?

A.	8 V
B.	320 V
C.	3.2 V
D.	32 V

Answer: Option D

Explanation:

No answer description available for this question.

13.

The current through a flashlight bulb is 40 mA and the total battery voltage is 4.5 V. The resistance of the bulb is approximately

A.	112 Ω
B.	11.2 Ω
C.	1.2Ω
D.	18Ω

Answer: Option A

Explanation:

No answer description available for this question.

14.

You are measuring the current in a circuit that is operated on an 18 V battery. The ammeter reads 40 mA. Later you notice the current has dropped to 20 mA. How much has the voltage changed?

A.	9 V
B.	900 mV
C.	0 V
D.	18 V

Answer: Option A

Explanation:

No answer description available for this question.

15.

A resistance of 3.3 M is connected across a 500 V source. The resulting current is approximately

A.	15.1 µA
B.	151 µA
C.	66 mA
D.	660 mA

Answer: Option B

Explanation:

No answer description available for this question.

16.

When there is 12 mA of current through a 1.2 k resistor, the voltage across the resistor is

A.	14.4 V
B.	1.4 V
C.	100 V
D.	10 V

Answer: Option A

Explanation:

V = IR (Ohms Law)

= 12 X 10^-3 X 1.2 X 10 ³

= 12 X 1.2

= 14.4 V

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