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Internetworking - Internetworking (2)

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  • Internetworking - Internetworking
9. 

Which of the following types of connections can use full duplex?

  1. Hub to hub
  2. Switch to switch
  3. Host to host
  4. Switch to hub
  5. Switch to host
A. 1, 2 and 4
B. 3 and 4
C. 3 and 5
D. 2, 3 and 5

Answer: Option D

Explanation:

Hubs cannot run full-duplex Ethernet. Full duplex must be used on a point-to-point connection between two devices capable of running full duplex. Switches and hosts can run full duplex between each other, but a hub can never run full duplex.

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10. 

How does a host on an Ethernet LAN know when to transmit after a collision has occurred?

  1. In a CSMA/CD collision domain, multiple stations can successfully transmit data simultaneously.
  2. In a CSMA/CD collision domain, stations must wait until the media is not in use before transmitting.
  3. You can improve the CSMA/CD network by adding more hubs.
  4. After a collision, the station that detected the collision has first priority to resend the lost data.
  5. After a collision, all stations run a random backoff algorithm. When the backoff delay period has expired, all stations have equal priority to transmit data.
A. 1 and 3
B. 2 and 4
C. 1,3 and 4
D. 2 and 5

Answer: Option D

Explanation:

Once transmitting stations on an Ethernet segment hear a collision, they send an extended jam signal to ensure that all stations recognize the collision. After the jamming is complete, each sender waits a predetermined amount of time, plus a random time. After both timers expire, they are free to transmit, but they must make sure the media is clear before transmitting and that they all have equal priority.

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11. 

What are two purposes for segmentation with a bridge?

  1. To add more broadcast domains.
  2. To create more collision domains.
  3. To add more bandwidth for users.
  4. To allow more broadcasts for users.
A. 1 only
B. 2 and 3
C. 2 and 4
D. 4 only

Answer: Option B

Explanation:

Bridges break up collision domains, which allow more bandwidth for users.

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12. 

Which of the following are types of flow control?

  1. Buffering
  2. Cut-through
  3. Windowing
  4. Congestion avoidance
A. 1 and 2
B. 1, 3 and 4
C. 2 only
D. 3 only

Answer: Option B

Explanation:

The common types of flow control are buffering, windowing, and congestion avoidance.

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13. 

Which three statements are true about the operation of a full-duplex Ethernet network?

  1. There are no collisions in full-duplex mode.
  2. A dedicated switch port is required for each full-duplex node.
  3. Ethernet hub ports are preconfigured for full-duplex mode.
  4. In a full-duplex environment, the host network card must check for the availability of the network media before transmitting.
  5. The host network card and the switch port must be capable of operating in full-duplex mode.
A. 1, 2, and 5
B. 2 and 4
C. 2, 3 and 4
D. 5 only

Answer: Option A

Explanation:

Full-duplex means you are using both wire pairs simultaneously to send and receive data. You must have a dedicated switch port for each node, which means you will not have collisions. Both the host network card and the switch port must be capable and set to work in full-duplex mode.

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14. 

What is the purpose of flow control?

A. To ensure that data is retransmitted if an acknowledgment is not received.
B. To reassemble segments in the correct order at the destination device.
C. To provide a means for the receiver to govern the amount of data sent by the sender.
D. To regulate the size of each segment.

Answer: Option C

Explanation:

Flow control allows the receiving device to control the transmitter so the receiving device's buffer does not overflow.

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15. 

What are the decimal and hexadecimal equivalents for the binary number 10110111?

A. 69/0x2102
B. 183/B7
C. 173/A6
D. 83/0xC5

Answer: Option B

Explanation:

You must be able to take a binary number and convert it into both decimal and hexadecimal. To convert to decimal, just add up the 1s using their values. The values that are turned on with the binary number of 10110111 are 128 + 32 + 16 + 4 + 2 + 1 = 183. To get the hexadecimal equivalent, you need to break the eight binary digits into nibbles (4 bits), 1011 and 0111. By add- ing up these values, you get 11 and 7. In hexadecimal, 11 is B, so the answer is 0xB7.

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16. 

A receiving host has failed to receive all of the segments that it should acknowledge. What can the host do to improve the reliability of this communication session?

A. Send a different source port number.
B. Restart the virtual circuit.
C. Decrease the sequence number.
D. Decrease the window size.

Answer: Option D

Explanation:

A receiving host can control the transmitter by using flow control (TCP uses Windowing by default). By decreasing the window size, the receiving host can slow down the transmitting host so the receiving host does not overflow its buffers.

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