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Physical Database Design - General Questions (2)

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  • Physical Database Design - General Questions
9. 

Which of the following improves a query's processing time?

A. Write complex queries.
B. Combine a table with itself.
C. Query one query within another.
D. Use compatible data types.

Answer: Option D

Explanation:

No answer description available for this question. Let us discuss.

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10. 

The blocking factor is:

A. a group of fields stored in adjacent memory.
B. the number of physical records per page.
C. attributes grouped together by the same primary key.
D. attributes grouped together by the same secondary key.

Answer: Option B

Explanation:

No answer description available for this question. Let us discuss.

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11. 

Which of the following is an advantage of partitioning?

A. Complexity
B. Inconsistent access speed
C. Extra space
D. Security

Answer: Option D

Explanation:

No answer description available for this question. Let us discuss.

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12. 

If a denormalization situation exists with a many-to-many or associative binary relationship, which of the following is true?

A. All fields are stored in one relation.
B. All fields are stored in two relations.
C. All fields are stored in three relations.
D. All fields are stored in four relations.

Answer: Option B

Explanation:

No answer description available for this question. Let us discuss.

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13. 

What is the best data type definition for Oracle when a field is alphanumeric and has a length that can vary?

A. VARCHAR2
B. CHAR
C. LONG
D. NUMBER

Answer: Option A

Explanation:

No answer description available for this question. Let us discuss.

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14. 

Selecting a data type involves which of the following?

A. Maximize storage space
B. Represent most values
C. Improve data integrity
D. All of the above.

Answer: Option C

Explanation:

No answer description available for this question. Let us discuss.

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15. 

If a denormalization situation exists with a one-to-one binary relationship, which of the following is true?

A. All fields are stored in one relation.
B. All fields are stored in two relations.
C. All fields are stored in three relations.
D. All fields are stored in four relations.

Answer: Option A

Explanation:

No answer description available for this question. Let us discuss.

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