Floating Point Issues

Which of the following statement obtains the remainder on dividing 5.5 by 1.3 ?

A.	rem = (5.5 % 1.3)
B.	rem = modf(5.5, 1.3)
C.	rem = fmod(5.5, 1.3)
D.	Error: we can't divide

Answer: Option C

Explanation:

fmod(x,y) - Calculates x modulo y, the remainder of x/y.
This function is the same as the modulus operator. But fmod() performs floating point divisions.

Example:


#include <stdio.h>
#include <math.h>

int main ()
{
  printf ("fmod of 5.5 by 1.3 is %lf\n", fmod (5.5, 1.3) );
  return 0;
}

Output:
fmod of 5.5 by 1.3 is 0.300000

What will you do to treat the constant 3.14 as a float?

A.	use float(3.14f)
B.	use 3.14f
C.	use f(3.14)
D.	use (f)(3.14)

Answer: Option B

Explanation:

Given 3.14 is a double constant.
To specify 3.14 as float, we have to add f to the 3.14. (i.e 3.14f)

A float occupies 4 bytes. If the hexadecimal equivalent of these 4 bytes are A, B, C and D, then when this float is stored in memory in which of the following order do these bytes gets stored?

A.	ABCD
B.	DCBA
C.	0xABCD
D.	Depends on big endian or little endian architecture

Answer: Option D

Explanation:

No answer description available for this question. Let us discuss.

The binary equivalent of 5.375 is

A.	101.101110111
B.	101.011
C.	101011
D.	None of above

Answer: Option B

Explanation:

No answer description available for this question. Let us discuss.

We want to round off x, a float, to an int value, The correct way to do is

A.	y = (int)(x + 0.5)
B.	y = int(x + 0.5)
C.	y = (int)x + 0.5
D.	y = (int)((int)x + 0.5)

Answer: Option A

Explanation:

Rounding off a value means replacing it by a nearest value that is approximately equal or smaller or greater to the given number.

y = (int)(x + 0.5); here x is any float value. To roundoff, we have to typecast the value of x by using (int)

Example:


#include <stdio.h>

int main ()
{
  float x = 3.6;
  int y = (int)(x + 0.5);
  printf ("Result = %d\n", y );
  return 0;
}

Output:
Result = 4.

Which statement will you add in the following program to work it correctly?

#include<stdio.h>
int main()
{
printf("%f\n", log(36.0));
return 0;
}

A.	#include
B.	#include
C.	#include
D.	#include

Answer: Option B

Explanation:

math.h is a header file in the standard library of C programming language designed for basic mathematical operations.

Declaration syntax: double log(double);

Which of the following range is a valid long double (Turbo C in 16 bit DOS OS) ?

A.	3.4E-4932 to 1.1E+4932
B.	3.4E-4932 to 3.4E+4932
C.	1.1E-4932 to 1.1E+4932
D.	1.7E-4932 to 1.7E+4932

Answer: Option A

Explanation:

The range of long double is 3.4E^-4932 to 1.1E⁺⁴⁹³²

If the binary eauivalent of 5.375 in normalised form is 0100 0000 1010 1100 0000 0000 0000 0000, what will be the output of the program (on intel machine)?

#include<stdio.h>
#include<math.h>
int main()
{
    float a=5.375;
    char *p;
    int i;
    p = (char*)&a;
    for(i=0; i<=3; i++)
        printf("%02x\n", (unsigned char)p[i]);
    return 0;
}

A.	40 AC 00 00
B.	04 CA 00 00
C.	00 00 AC 40
D.	00 00 CA 04

Answer: Option C

Explanation:

No answer description available for this question. Let us discuss.

Floating Point Issues

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