IndiaBIX
IndiaBIX
Start typing & press "Enter" or "ESC" to close
  • Home
  • Jobs
  • Results
  • Current Affairs
  • GK
  • Online Test
  • HR Interview
  • BLOG

Pipes and Cistern- General Questions (2)

  • Home
  • Aptitude
  • Pipes and Cistern
  • Pipes and Cistern- General Questions
9. 

A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?

A. 20 hours
B. 25 hours
C. 35 hours
D. Cannot be determined
E. None of these

Answer: Option C

Explanation:

Suppose pipe A alone takes x hours to fill the tank.

Then, pipes B and C will take x and x hours respectively to fill the tank.
2 4
1 + 2 + 4 = 1
x x x 5
7 = 1
x 5

 x = 35 hrs.

View Answer Discuss Workspace Report

10. 

Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is:

A. 60 gallons
B. 100 gallons
C. 120 gallons
D. 180 gallons

Answer: Option C

Explanation:

 

Work done by the waste pipe in 1 minute = 1 - 1-sym-oparen-h1 1 + 1 1-sym-cparen-h1
15 20 24
    = 1-sym-oparen-h1 1 - 11 1-sym-cparen-h1
15 120
    = -  1 .    [-ve sign means emptying]
40
 Volume of 1 part = 3 gallons.
40

Volume of whole = (3 x 40) gallons = 120 gallons.

View Answer Discuss Workspace Report

11. 

A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is:

A. 6 hours
B. 10 hours
C. 15 hours
D. 30 hours

Answer: Option C

Explanation:

Suppose, first pipe alone takes x hours to fill the tank .

Then, second and third pipes will take (x -5) and (x - 9) hours respectively to fill the tank.

1 + 1 = 1
x (x - 5) (x - 9)
x - 5 + x = 1
x(x - 5) (x - 9)

 (2x - 5)(x - 9) = x(x - 5)

 x2 - 18x + 45 = 0

(x - 15)(x - 3) = 0

 x = 15.    [neglecting x = 3]

View Answer Discuss Workspace Report

12. 

Two pipes A and B can fill a cistern in 371-div-1by2minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the B is turned off after:

A. 5 min.
B. 9 min.
C. 10 min.
D. 15 min.

Answer: Option B

Explanation:

Let B be turned off after x minutes. Then,

Part filled by (A + B) in x min. + Part filled by A in (30 -x) min. = 1.

 x 1-sym-oparen-h1 2 + 1 1-sym-cparen-h1 + (30 - x). 2 = 1
75 45 75
11x + (60 -2x) = 1
225 75

 11x + 180 - 6x = 225.

 x = 9.

View Answer Discuss Workspace Report

13. 

A pump can fill a tank with water in 2 hours. Because of a leak, it took 21-div-1by3hours to fill the tank. The leak can drain all the water of the tank in:

A. 4 1/3 hours
B. 7 hours
C. 8 hours
D. 14 hours

Answer: Option D

Explanation:

Work done by the leak in 1 hour = 1-sym-oparen-h1 1 - 3 1-sym-cparen-h1 = 1 .
2 7 14

 Leak will empty the tank in 14 hrs.

View Answer Discuss Workspace Report

14. 

Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:

A. 1 13/17 hours
B. 2 8/11 hours
C. 3 9/17 hours
D. 4 1/2 hours

Answer: Option C

Explanation:

 

Net part filled in 1 hour 1-sym-oparen-h1 1 + 1 - 1 1-sym-cparen-h1 = 17 .
5 6 12 60
 The tank will be full in 60 hours i.e., 3 9 hours.
17 17
View Answer Discuss Workspace Report

15. 

Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?

A. 5/11
B. 6/11
C. 7/11
D. 8/11

Answer: Option B

Explanation:

 

Part filled by (A + B + C) in 3 minutes = 3 1-sym-oparen-h1 1 + 1 + 1 1-sym-cparen-h1 = 1-sym-oparen-h1 3 x 11 1-sym-cparen-h1 = 11 .
30 20 10 60 20
Part filled by C in 3 minutes = 3 .
10
 Required ratio = 1-sym-oparen-h1 3 x 20 1-sym-cparen-h1 = 6 .
10 11 11
View Answer Discuss Workspace Report

  • 1
  • 2

Questions & Answers

Aptitude Chemical Engineering Civil Engineering Computer Science & Engineering Current Affairs Data Interpretation Electrical & Electronics Engineering Electronics & Communication Engineering General Knowledge Logical Reasoning Mechanical Engineering Non Verbal Reasoning Verbal Ability Verbal Reasoning

Interviews

HR Interview

Jobs

Sarkari Jobs

Results

Rojgar ResultSarkari Result

Admission

Admission 2023

Admit Card

Admit Card 2023

Answer Key

Answer Key 2023
copyright
Privacy Policy
© 2025 IndiaBIX. All Rights Reserved.

Report