Area - General Questions

A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:

A.	Rs. 456
B.	Rs. 458
C.	Rs. 558
D.	Rs. 568

Answer: Option C

Explanation:

Area to be plastered	= [2(l + b) x h] + (l x b)
	= {[2(25 + 12) x 6] + (25 x 12)} m²
	= (444 + 300) m²
	= 744 m².

Cost of plastering = Rs.		744 x	75		= Rs. 558.
			100

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

A.	34
B.	40
C.	68
D.	88

Answer: Option D

Explanation:

We have: l = 20 ft and lb = 680 sq. ft.

So, b = 34 ft.

Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.

The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

A.	40
B.	50
C.	120
D.	Data inadequate
E.	None of these

Answer: Option E

Explanation:

Let breadth = x metres.

Then, length = (x + 20) metres.

Perimeter =		5300		m = 200 m.
		26.50

2[(x + 20) + x] = 200

2x + 20 = 100

2x = 80

x = 40.

Hence, length = x + 20 = 60 m.

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A.	25% increase
B.	50% increase
C.	50% decrease
D.	75% decrease

Answer: Option B

Explanation:

Let original length = x and original breadth = y.

Original area = xy.

New length =	x	.
	2

New breadth = 3y.

New area =		x	x 3y		=	3	xy.
		2				2

Increase % =		1	xy x	1	x 100	%	= 50%.
		2		xy

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

A.	1520 m2
B.	2420 m2
C.	2480 m2
D.	2520 m2

Answer: Option D

Explanation:

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.

Solving the two equations, we get: l = 63 and b = 40.

Area = (l x b) = (63 x 40) m² = 2520 m².

What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?

A.	814
B.	820
C.	840
D.	844

Answer: Option A

Explanation:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.

Area of each tile = (41 x 41) cm².

Required number of tiles =		1517 x 902		= 814.
		41 x 41

The diagonal of a rectangle is √41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:

A.	9 cm
B.	18 cm
C.	20 cm
D.	41 cm

Answer: Option B

Explanation:

√l² + b² = √41.

Also, lb = 20.

(l + b)² = (l² + b²) + 2lb = 41 + 40 = 81

(l + b) = 9.

Perimeter = 2(l + b) = 18 cm.

A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

A.	20
B.	24
C.	30
D.	33

Answer: Option C

Explanation:

Let the side of the square(ABCD) be x metres.

Then, AB + BC = 2x metres. 1-z-526-061

AC = 2x = (1.41x) m.

Saving on 2x metres = (0.59x) m.

Saving % =		0.59x	x 100	%	= 30% (approx.)
		2x

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