Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

1.

Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

[A].	9
[B].	11
[C].	13
[D].	15

Answer: Option D

Explanation:

Let the three integers be x, x + 2 and x + 4.

Then, 3x = 2(x + 4) + 3 x = 11.

Third integer = x + 4 = 15.

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