Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option A
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
8x + 16 = 5x + 40
3x = 24
x = 8.