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Problems on Ages - General Questions

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  • Problems on Ages
  • Problems on Ages - General Questions
1. 

The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:

A. 5 : 2
B. 7 : 3
C. 9 : 2
D. 13 : 4

Answer: Option B

Explanation:

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[(x + 10) + 10]

 3x + 20 = 2x + 40

 x = 20.

 Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.

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2. 

Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q's age?

A. 1 year
B. 2 years
C. 25 years
D. Data inadequate
E. None of these

Answer: Option D

Explanation:

Given that:

1. The difference of age b/w R and Q = The difference of age b/w Q and T.

2. Sum of age of R and T is 50 i.e. (R + T) = 50.

Question: R - Q = ?.

Explanation:

R - Q = Q - T

(R + T) = 2Q

Now given that, (R + T) = 50

So, 50 = 2Q and therefore Q = 25.

Question is (R - Q) = ?

Here we know the value(age) of Q (25), but we don't know the age of R.

Therefore, (R-Q) cannot be determined.

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3. 

A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?

A. 32 years
B. 36 years
C. 40 years
D. 48 years

Answer: Option C

Explanation:

Let the mother's present age be x years.

Then, the person's present age = 1-sym-oparen-h1 2 x 1-sym-cparen-h1 years.
5
1-sym-oparen-h1 2 x + 8 1-sym-cparen-h1 = 1 (x + 8)
5 2

 2(2x + 40) = 5(x + 8)

 x = 40.

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4. 

Ayesha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?

A. 2 years
B. 4 years
C. 6 years
D. 8 years

Answer: Option C

Explanation:

Mother's age when Ayesha's brother was born = 36 years.

Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.

 Required difference = (42 - 36) years = 6 years.

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5. 

The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

A. 8, 20, 28
B. 16, 28, 36
C. 20, 35, 45
D. None of these

Answer: Option B

Explanation:

Let their present ages be 4x, 7x and 9x years respectively.

Then, (4x - 8) + (7x - 8) + (9x - 8) = 56

 20x = 80

 x = 4.

 Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.

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6. 

Sachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7 : 9, how old is Sachin?

A. 16 years
B. 18 years
C. 28 years
D. 24.5 years
E. None of these

Answer: Option D

Explanation:

Let Rahul's age be x years.

Then, Sachin's age = (x - 7) years.

x - 7 = 7
x 9

 9x - 63 = 7x

 2x = 63

 x = 31.5

Hence, Sachin's age =(x - 7) = 24.5 years.

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7. 

At present, the ratio between the ages of Arun and Deepak is 4 : 3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present ?

A. 12 years
B. 15 years
C. 19 and half
D. 21 years

Answer: Option B

Explanation:

Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,

4x + 6 = 26        4x = 20

x = 5.

 Deepak's age = 3x = 15 years.

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8. 

The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:

A. 12 years
B. 14 years
C. 18 years
D. 20 years

Answer: Option D

Explanation:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 6 = 5(x - 6)

 54 - x = 5x - 30

 6x = 84

 x = 14.

 Son's age after 6 years = (x+ 6) = 20 years.

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