From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

1.

From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

[A].	149 m
[B].	156 m
[C].	173 m
[D].	200 m

Answer: Option C

Explanation:

Let AB be the tower.

1-z-646-002

Then, APB = 30° and AB = 100 m.

AB	= tan 30° =	1
AP	= tan 30° =	3

AP	= (AB x 3) m
	= 1003 m
	= (100 x 1.73) m
	= 173 m.

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