A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

Area of the park = (60 x 40) m² = 2400 m².

Area of the lawn = 2109 m².

 Area of the crossroads = (2400 - 2109) m² = 291 m².

Let the width of the road be x metres. Then,

60x + 40x - x² = 291

 x² - 100x + 291 = 0

 (x - 97)(x - 3) = 0

 x = 3.