Online Aptitude Test

Online Aptitude Test - Aptitude

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This is a FREE online test. DO NOT pay money to anyone to attend this test.
Total number of questions : 20.
Time alloted : 30 minutes.
Each question carry 1 mark, no negative marks.
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All the best :-).

A man buys a watch for Rs. 1950 in cash and sells it for Rs. 2200 at a credit of 1 year. If the rate of interest is 10% per annum, the man:

	A.	gains Rs. 55
	B.	gains Rs. 50
	C.	loses Rs. 30
	D.	gains Rs. 30

Your Answer: Option

Correct Answer: Option B

Explanation:

S.P.

= P.W. of Rs. 2200 due 1 year hence

= Rs.		2200 x 100
		100 + (10 x 1)

= Rs. 2000.

Gain = Rs. (2000 - 1950) = Rs. 50.

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The banker's discount on a certain sum due 2 years hence is	11	of the true discount.
	10

The rate percent is:

	A.	11%
	B.	10%
	C.	5%
	D.	5.5%

Your Answer: Option

Correct Answer: Option C

Explanation:

Let T.D. be Re. 1.

Then, B.D. = Rs.	11	= Rs. 1.10.
	10

Sum = Rs.		1.10 x 1		= Rs.		110		= Rs. 11.
		1.10 - 1				10

S.I. on Rs. 11 for 2 years is Rs. 1.10

Rate =		100 x 1.10	%	= 5%.
		11 x 2

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√1.5625 = ?

	A.	1.05
	B.	1.25
	C.	1.45
	D.	1.55

Your Answer: Option

Correct Answer: Option B

Explanation:

   1|1.5625( 1.25
    |1
    |-------
  22| 56
    | 44
    |-------
 245| 1225
    | 1225
    |-------
    |    X
    |-------

√1.5625 = 1.25.

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A, B and C enter into a partnership in the ratio 1-div-7by2 : 1-div-4by3 : 1-div-6by5 After 4 months, A increases his share 50%. If the total profit at the end of one year be Rs. 21,600, then B's share in the profit is:

	A.	Rs. 2100
	B.	Rs. 2400
	C.	Rs. 3600
	D.	Rs. 4000

Your Answer: Option

Correct Answer: Option D

Explanation:

Ratio of initial investments =		7	:	4	:	6		= 105 : 40 : 36.
		2		3		5

Let the initial investments be 105x, 40x and 36x.

A : B : C =		105x x 4 +	150	x 105x x 8		: (40x x 12) : (36x x 12)
			100

= 1680x : 480x : 432x = 35 : 10 : 9.

Hence, B's share = Rs.		21600 x	10		= Rs. 4000.
			54

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The average weight of 16 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.

	A.	47.55 kg
	B.	48 kg
	C.	48.55 kg
	D.	49.25 kg

Your Answer: Option

Correct Answer: Option C

Explanation:

Required average

=		50.25 x 16 + 45.15 x 8
		16 + 8

=		804 + 361.20
		24

=	1165.20
	24

= 48.55

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The H.C.F. of	9	,	12	,	18	and	21	is:
	10		25		35		40

	A.	3/5
	B.	252/5
	C.	3/1400
	D.	63/700

Your Answer: Option

Correct Answer: Option C

Explanation:

Required H.C.F. =	H.C.F. of 9, 12, 18, 21	=	3
	L.C.M. of 10, 25, 35, 40		1400

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A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:

	A.	30 birds
	B.	60 birds
	C.	72 birds
	D.	90 birds

Your Answer: Option

Correct Answer: Option A

Explanation:

Let the total number of shots be x. Then,

Shots fired by A =	5	x
	8

Shots fired by B =	3	x
	8

Killing shots by A =	1	of	5	x	=	5	x
	3		8			24

Shots missed by B =	1	of	3	x	=	3	x
	2		8			16

	3x	= 27 or x =		27 x 16		= 144.
	16			3

Birds killed by A =	5x	=		5	x 144		= 30.
	24			24

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If (64)2 - (36)2 = 20 x x, then x = ?

	A.	70
	B.	120
	C.	180
	D.	140
	E.	None of these

Your Answer: Option

Correct Answer: Option D

Explanation:

20 x x = (64 + 36)(64 - 36) = 100 x 28

x =	100 x 28	= 140
	20

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The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:

	A.	17 kg
	B.	20 kg
	C.	26 kg
	D.	31 kg

Your Answer: Option

Correct Answer: Option D

Explanation:

Let A, B, C represent their respective weights. Then, we have:

A + B + C = (45 x 3) = 135 .... (i)

A + B = (40 x 2) = 80 .... (ii)

B + C = (43 x 2) = 86 ....(iii)

Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)

Subtracting (i) from (iv), we get : B = 31.

B's weight = 31 kg.

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10.

A jar full of whisky contains 40% alcohol. A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is:

	A.	1/3
	B.	2/3
	C.	2/5
	D.	3/5

Your Answer: Option

Correct Answer: Option B

Explanation:

By the rule of alligation, we have:

Strength of first jarStrength of 2^nd jar
40%	Mean Strength 26%	19%
7		14

So, ratio of 1^st and 2^nd quantities = 7 : 14 = 1 : 2

Required quantity replaced =	2
	3

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11.

A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

	A.	220 km
	B.	224 km
	C.	230 km
	D.	234 km

Your Answer: Option

Correct Answer: Option B

Explanation:

(1/2)x	+	(1/2)x	= 10
21		24

	x	+	x	= 20
	21		24

15x = 168 x 20

x =		168 x 20		= 224 km.
		15

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12.

397 x 397 + 104 x 104 + 2 x 397 x 104 = ?

	A.	250001
	B.	251001
	C.	260101
	D.	261001

Your Answer: Option

Correct Answer: Option B

Explanation:

Given Exp.	= (397)² + (104)² + 2 x 397 x 104
	= (397 + 104)²
	= (501)² = (500 + 1)²
	= (500²) + (1)² + (2 x 500 x 1)
	= 250000 + 1 + 1000
	= 251001

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13.

In Arun's opinion, his weight is greater than 65 kg but less than 72 kg. His brother doest not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun?

	A.	67 kg.
	B.	68 kg.
	C.	69 kg.
	D.	Data inadequate
	E.	None of these

Your Answer: Option

Correct Answer: Option A

Explanation:

Let Arun's weight by X kg.

According to Arun, 65 < X < 72

According to Arun's brother, 60 < X < 70.

According to Arun's mother, X <= 68

The values satisfying all the above conditions are 66, 67 and 68.

Required average =		66 + 67 + 68		=		201		= 67 kg.
		3				3

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14.

A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B's share?

	A.	Rs. 500
	B.	Rs. 1500
	C.	Rs. 2000
	D.	None of these

Your Answer: Option

Correct Answer: Option C

Explanation:

Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.

Then, 4x - 3x = 1000

x = 1000.

B's share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.

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15.

The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?

	A.	0
	B.	1
	C.	10
	D.	19

Your Answer: Option

Correct Answer: Option D

Explanation:

Average of 20 numbers = 0.

Sum of 20 numbers (0 x 20) = 0.

It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).

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16.

A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is:

	A.	45 m
	B.	50 m
	C.	54 m
	D.	72 m

Your Answer: Option

Correct Answer: Option B

Explanation:

2 kmph =		2 x	5		m/sec =	5	m/sec.
			18			9

4 kmph =		4 x	5		m/sec =	10	m/sec.
			18			9

Let the length of the train be x metres and its speed by y m/sec.

Then,

= 9 and

= 10.

y -	5
	9

y -	10
	9

Therefore 9y - 5 = x and 10(9y - 10) = 9x

9y - x = 5 and 90y - 9x = 100.

On solving, we get: x = 50.

Therefore Length of the train is 50 m.

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17.

Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A : B.

	A.	2 : 3
	B.	1 : 1
	C.	3 : 4
	D.	4 : 3

Your Answer: Option

Correct Answer: Option D

Explanation:

5% of A + 4% of B =	2	(6% of A + 8% of B)
	3

	5	A +	4	B	=	2		6	A +	8	B
	100		100			3		100		100

	1	A +	1	B	=	1	A +	4	B
	20		25			25		75

		1	-	1	A =		4	-	1	B
		20		25			75		25

	1	A =	1	B
	100		75

A	=	100	=	4	.
B		75		3

Required ratio = 4 : 3

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18.

A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?

	A.	10/21
	B.	11/21
	C.	2/7
	D.	5/7

Your Answer: Option

Correct Answer: Option A

Explanation:

Total number of balls = (2 + 3 + 2) = 7.

Let S be the sample space.

Then, n(S)

= Number of ways of drawing 2 balls out of 7

= ⁷C₂ `

=	(7 x 6)
	(2 x 1)

= 21.

Let E = Event of drawing 2 balls, none of which is blue.

n(E)

= Number of ways of drawing 2 balls out of (2 + 3) balls.

= ⁵C₂

=	(5 x 4)
	(2 x 1)

= 10.

P(E) =	n(E)	=	10	.
	n(S)		21

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19.

If x and y are positive integers such that (3x + 7y) is a multiple of 11, then which of the following will be divisible by 11 ?

	A.	4x + 6y
	B.	x + y + 4
	C.	9x + 4y
	D.	4x - 9y

Your Answer: Option

Correct Answer: Option D

Explanation:

By hit and trial, we put x = 5 and y = 1 so that (3x + 7y) = (3 x 5 + 7 x 1) = 22, which is divisible by 11.

(4x + 6y) = ( 4 x 5 + 6 x 1) = 26, which is not divisible by 11;

(x + y + 4 ) = (5 + 1 + 4) = 10, which is not divisible by 11;

(9x + 4y) = (9 x 5 + 4 x 1) = 49, which is not divisible by 11;

(4x - 9y) = (4 x 5 - 9 x 1) = 11, which is divisible by 11.

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20.

In how many different ways can the letters of the word 'MATHEMATICS' be arranged so that the vowels always come together?

	A.	10080
	B.	4989600
	C.	120960
	D.	None of these

Your Answer: Option

Correct Answer: Option C

Explanation:

In the word 'MATHEMATICS', we treat the vowels AEAI as one letter.

Thus, we have MTHMTCS (AEAI).

Now, we have to arrange 8 letters, out of which M occurs twice, T occurs twice and the rest are different.

Number of ways of arranging these letters =	8!	= 10080.
	(2!)(2!)

Now, AEAI has 4 letters in which A occurs 2 times and the rest are different.

Number of ways of arranging these letters =	4!	= 12.
	2!

Required number of words = (10080 x 12) = 120960.

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