Force Vectors - General Questions

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Force Vectors - General Questions

pg2-8

Determine the design angle thetaa for connecting member A to the plate if the resultant force is to be directed vercially upward. Also, what is the magnitude of the resultant?

A.	R = 400 N, = 53.5°
B.	R = 250 N, = 30.0°
C.	R = 300 N, = 36.9°
D.	R = 640 N, = 38.6°

Answer: Option C

Explanation:

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pg2-16

Determine the magnitude and direction angles of F₂, so that the resultant of the two forces acts upward along the z axis of the pole and has a magnitude of 275 N.

A.	F2 = 246 N, = 54.9°, = 114.0°, = 44.7°
B.	F2 = 200 N, = 45.0°, = -60.0°, = 29.0°
C.	F2 = 200 N, = 45.0°, = 120.0°, = 29.0°
D.	F2 = 246 N, = 54.9°, = 66.0°, = 44.7°

Answer: Option A

Explanation:

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pg2-13

Express each force in Cartesian vector form.

A.	F1 = (2.50 i + 3.54 j + 2.50 k) kN, F2 = -2 j kN
B.	F1 = (4.33 i + 3.54 j + 4.33 k) kN, F2 = -2 j kN
C.	F1 = (2.17 i + 3.75 j + 4.33 k) kN, F2 = -2 j kN
D.	F1 = (4.33 i + 3.75 j + 2.17 k) kN, F2 = -2 j kN

Answer: Option A

Explanation:

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pg2-4

Determine the magnitude and direction thetaa of F so that this force has components of 40 lb acting from A toward B and 60lb acting from A toward C on the frame.

A.	F = 44.7 lb, = 22.9°
B.	F = 80.3 lb, = 46.2°
C.	F = 62.9 lb, = 37.1°
D.	F = 72.1 lb, = 56.3°

Answer: Option B

Explanation:

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pg2-5

Determine the design angle thetaa ( thetaa <90°) bretween the two struts so that the 500-lb horizontal force has a component of 600lb directed from A toward C. That is the component of force acting along member AB?

A.	FAB = 321 lb, = 40.0°
B.	FAB = 383 lb, = 36.9°
C.	FAB = 171.1 lb, = 20.0°
D.	FAB = 215 lb, = 52.7°

Answer: Option D

Explanation:

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pg2-1

Determine the magnitudes of the resultant force and its direction measured from the positive x axis.

A.	R = 12.49 kN, = 43.9° CW
B.	R = 13.6 kN, = 21.5° CW
C.	R = 14.00 kN, = 60.0° CW
D.	R = 10.80 kN, = 68.2° CW

Answer: Option A

Explanation:

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pg2-26

Cable BC exerts a force of F = 28 N on the top of the flagpole. Determine the projection of this force along the positive z axis of the pole.

A.	F = 24 N
B.	F = -24 N
C.	F = 12 N
D.	F = 12 N

Answer: Option B

Explanation:

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pg2-2

Determine the magnitude of the x and y components of the 2—kN force.

A.	Fx = -1.414 kN, Fy = -1.414 kN
B.	Fx = -1.000 kN, Fy = -1.732 kN
C.	Fx = -1.732 kN, Fy = -1.000 kN
D.	Fx = -4.000 kN, Fy = -2.312 kN

Answer: Option B

Explanation:

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Force Vectors - General Questions

Force Vectors - General Questions

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