Calendar - General Questions

The year 2007 is an ordinary year. So, it has 1 odd day.

1^st day of the year 2007 was Monday.

1^st day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.

The year 2008 is a leap year. So, it has 2 odd days.

1^st day of the year 2008 is Tuesday (Given)

So, 1^st day of the year 2009 is 2 days beyond Tuesday.

Hence, it will be Thursday.

The year 2006 is an ordinary year. So, it has 1 odd day.

So, the day on 8^th Dec, 2007 will be 1 day beyond the day on 8^th Dec, 2006.

But, 8^th Dec, 2007 is Saturday.

 8^th Dec, 2006 is Friday.

The century divisible by 400 is a leap year.

 The year 700 is not a leap year.

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

Year    : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd day : 1    2    1    1    1    2    1    1    1    2    1    

Sum = 14 odd days  0 odd days.

 Calendar for the year 2018 will be the same as for the year 2007.

The year 2004 is a leap year. It has 2 odd days.

 The day on 8^th Feb, 2004 is 2 days before the day on 8^th Feb, 2005.

Hence, this day is Sunday.

100 years contain 5 odd days.

 Last day of 1^st century is Friday.

200 years contain (5 x 2)  3 odd days.

 Last day of 2^nd century is Wednesday.

300 years contain (5 x 3) = 15  1 odd day.

 Last day of 3^rd century is Monday.

400 years contain 0 odd day.

 Last day of 4^th century is Sunday.

This cycle is repeated.

 Last day of a century cannot be Tuesday or Thursday or Saturday.

x weeks x days = (7x + x) days = 8x days.