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What will be the output of the program? class BitShift { public static void main(String args) { int x = 0x80000000; System.out.print(x + " and "); x = x >>> 31; System.out.println(x); } }

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1. 

What will be the output of the program?

class BitShift
{
public static void main(String [] args)
{
int x = 0x80000000;
System.out.print(x + " and ");
x = x >>> 31;
System.out.println(x);
}
}

[A]. -2147483648 and 1
[B]. 0x80000000 and 0x00000001
[C]. -2147483648 and -1
[D]. 1 and -2147483648

Answer: Option A

Explanation:

Option A is correct. The >>> operator moves all bits to the right, zero filling the left bits. The bit transformation looks like this:

Before: 1000 0000 0000 0000 0000 0000 0000 0000

After: 0000 0000 0000 0000 0000 0000 0000 0001

Option C is incorrect because the >>> operator zero fills the left bits, which in this case changes the sign of x, as shown.

Option B is incorrect because the output method print() always displays integers in base 10.

Option D is incorrect because this is the reverse order of the two output numbers.

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