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What will be the output of the program? class PassA { public static void main(String args) { PassA p = new PassA(); p.start(); } void start() { long a1 = {3,4,5}; long a2 = fix(a1); System.out.print(a1 + a1 + a1 + " ")

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1. 

What will be the output of the program?

class PassA
{
public static void main(String [] args)
{
PassA p = new PassA();
p.start();
}

void start()
{
long [] a1 = {3,4,5};
long [] a2 = fix(a1);
System.out.print(a1[0] + a1[1] + a1[2] + " ");
System.out.println(a2[0] + a2[1] + a2[2]);
}

long [] fix(long [] a3)
{
a3[1] = 7;
return a3;
}
}

[A]. 12 15
[B]. 15 15
[C]. 3 4 5 3 7 5
[D]. 3 7 5 3 7 5

Answer: Option B

Explanation:

Output: 15 15

The reference variables a1 and a3 refer to the same long array object. When the [1] element is updated in the fix() method, it is updating the array referred to by a1. The reference variable a2 refers to the same array object.

So Output: 3+7+5+" "3+7+5

Output: 15 15 Because Numeric values will be added

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