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What will be the output of the program? class Exc0 extends Exception { } class Exc1 extends Exc0 { } /* Line 2 */ public class Test { public static void main(String args) { try { throw new Exc1(); /* Line 9 */ } catch (Exc0 e0) /* L

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1. 

What will be the output of the program?

class Exc0 extends Exception { }
class Exc1 extends Exc0 { } /* Line 2 */
public class Test
{
public static void main(String args[])
{
try
{
throw new Exc1(); /* Line 9 */
}
catch (Exc0 e0) /* Line 11 */
{
System.out.println("Ex0 caught");
}
catch (Exception e)
{
System.out.println("exception caught");
}
}
}

[A]. Ex0 caught
[B]. exception caught
[C]. Compilation fails because of an error at line 2.
[D]. Compilation fails because of an error at line 9.

Answer: Option A

Explanation:

An exception Exc1 is thrown and is caught by the catch statement on line 11. The code is executed in this block. There is no finally block of code to execute.

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