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What will be the output of the program? public class X { public static void main(String args) { try { badMethod(); System.out.print("A"); } catch (Exception ex) { System.out.print("B"); } finally { System.out.print("C");

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1. 

What will be the output of the program?

public class X
{
public static void main(String [] args)
{
try
{
badMethod();
System.out.print("A");
}
catch (Exception ex)
{
System.out.print("B");
}
finally
{
System.out.print("C");
}
System.out.print("D");
}
public static void badMethod()
{
throw new Error(); /* Line 22 */
}
}

[A]. ABCD
[B]. Compilation fails.
[C]. C is printed before exiting with an error message.
[D]. BC is printed before exiting with an error message.

Answer: Option C

Explanation:

Error is thrown but not recognised line(22) because the only catch attempts to catch an Exception and Exception is not a superclass of Error. Therefore only the code in the finally statement can be run before exiting with a runtime error (Exception in thread "main" java.lang.Error).

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