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A runs 1 2/3times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?

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1. 

A runs 11-div-2by3times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?

[A]. 200 m
[B]. 300 m
[C]. 270 m
[D]. 160 m

Answer: Option A

Explanation:

Ratio of the speeds of A and B = 5 : 1 = 5 : 3.
3

Thus, in race of 5 m, A gains 2 m over B.

2 m are gained by A in a race of 5 m.

80 m will be gained by A in race of 1-sym-oparen-h1 5 x 80 1-sym-cparen-h1m = 200 m.
2

 Winning post is 200 m away from the starting point.

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