A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:

Answer: Option D

Explanation:

Let the speed of the second train be x km/hr.

Relative speed

= (x + 50) km/hr

=		(x + 50) x	5		m/sec
			18

=		250 + 5x		m/sec.
		18

Distance covered = (108 + 112) = 220 m.

220

= 6

	250 + 5x
	18

250 + 5x = 660

x = 82 km/hr.