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Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.

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1. 

Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.

[A]. 12 sec
[B]. 24 sec
[C]. 48 sec
[D]. 60 sec

Answer: Option B

Explanation:

Relative speed = = (45 + 30) km/hr
 
= 1-sym-oparen-h1 75 x 5 1-sym-cparen-h1 m/sec
18
 
= 1-sym-oparen-h1 125 1-sym-cparen-h1 m/sec.
6

We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

So, distance covered = Length of the slower train.

Therefore, Distance covered = 500 m.

Therefore Required time = 1-sym-oparen-h1 500 x 6 1-sym-cparen-h1 = 24 sec.
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