The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

Let the numbers be 2x and 3x.

Then, their L.C.M. = 6x.

So, 6x = 48 or x = 8.

 The numbers are 16 and 24.

Hence, required sum = (16 + 24) = 40.