The smallest 5 digit number exactly divisible by 41 is:

1.

The smallest 5 digit number exactly divisible by 41 is:

[A].	1004
[B].	10004
[C].	10045
[D].	10025
[E].	None of these

Answer: Option B

Explanation:

The smallest 5-digit number = 10000.

 41) 10000 (243
     82
     ---
     180
     164
     ----
      160
      123
      ---
       37
      --- 

 Required number = 10000 + (41 - 37)
                 = 10004.

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