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A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?

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1. 

A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?

[A]. 1/3
[B]. 1/4
[C]. 1/5
[D]. 1/7

Answer: Option C

Explanation:

Suppose the vessel initially contains 8 litres of liquid.

Let x litres of this liquid be replaced with water.

Quantity of water in new mixture = 1-sym-oparen-h1 3 - 3x + x 1-sym-cparen-h1 litres
8
Quantity of syrup in new mixture = 1-sym-oparen-h1 5 - 5x 1-sym-cparen-h1 litres
8
1-sym-oparen-h1 3 - 3x + x 1-sym-cparen-h1 = 1-sym-oparen-h1 5 - 5x 1-sym-cparen-h1
8 8

 5x + 24 = 40 - 5x

 10x = 16

 x = 8 .
5
So, part of the mixture replaced = 8 x 1 = 1 .
5 8 5
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