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A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is

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1. 

A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is

[A]. 400 m
[B]. 450 m
[C]. 560 m
[D]. 600 m

Answer: Option A

Explanation:

Let the length of the first train be x metres.

Then, the length of the second train is 1-sym-oparen-h1 x 1-sym-cparen-h1 metres.
2
Relative speed = (48 + 42) kmph = 1-sym-oparen-h1 90 x 5 1-sym-cparen-h1 m/sec = 25 m/sec.
18
Therefore [x + (x/2)] = 12 or 3x = 300     or     x = 200.
25 2

Therefore Length of first train = 200 m.

Let the length of platform be y metres.

Speed of the first train = 1-sym-oparen-h1 48 x 5 1-sym-cparen-h1 m/sec = 40 m/sec.
18 3
Therefore (200 + y) x 3 = 45
40

=> 600 + 3y = 1800

=> y = 400 m.

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